Question : If $3x–3<3+\frac{x}{2}$ and $x–2\leq 6+2x$, then $x$ can take which of the following values?
Option 1: 6
Option 2: 2
Option 3: 10
Option 4: –10
Latest: SSC CGL Tier 1 Result 2024 Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 2
Solution : Given: $3x–3<3+\frac{x}{2}$ and $x–2\leq 6+2x$ Or, $3x–\frac{x}{2}<3+3$ and $–2–6\leq 2x–x$ Or, $\frac{6x–x}{2}<6$ and $–8\leq x$ Or, $\frac{5x}{2}<6$ and $–8\leq x$ Or, $5x<12$ and $–8\leq x$ Or, $x<\frac{12}{5}$ and $–8\leq x$ Or, $–8\leq x<2.4$ Amongst all the given values, 2 satisfies the above condition. Hence, the correct answer is 2.
Candidates can download this ebook to know all about SSC CGL.
Result | Eligibility | Application | Selection Process | Preparation Tips | Admit Card | Answer Key
Question : If $2x-6\leq x-3$ and $1+3x<4x+4$, then $x$ can take which of the following values?
Question : If $2x-4\leq \frac{2-x}{3}$ and $2(2x+5)>3x-5$, then $x$ can take which of the following values?
Question : If $2+4x<5-\frac{x}{2}$ and $3x+3>-5-3x$, then $x$ can take which of the following values?
Question : If $(x-\frac{1}{3x})=\frac{1}{3}$, then the value of $3(x-\frac{1}{3x})$ is:
Question : If $\frac {x^2+3x+1}{x^2–3x+1}=\frac{1}{2 }$, then the value of $(x+\frac{1}{x})$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile