Question : If $\frac{\cos\alpha}{\cos\beta}= m$ and $\frac{\cos\alpha}{\sin\beta}= n$, then the value of $(m^{2}+n^{2})\cos^{2}\beta$ is:
Option 1: n2
Option 2: m2
Option 3: mn
Option 4: 1
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Correct Answer: n 2
Solution : Given that $\frac{\cos\alpha }{\cos\beta }=m$ and $\frac{\cos\alpha }{\sin\beta }=n$, we can express $\cos\: \alpha$ in terms of $m$ and $n$ as follows: $⇒\cos\alpha = m×cos\beta =n× \sin\beta$ Squaring both sides, we get: $⇒(m × \cos\beta)^2 = (n × \sin\beta)^2$ This simplifies to: $⇒m^2 × \cos^2\beta = n^2 × (1 - \cos^2\beta)$ Rearranging terms, we get: $⇒m^2 × \cos^2\beta + n^2 × \cos^2\beta = n^2$ Factoring out $cos^2\beta$, we get: $⇒(m^2 + n^2) × \cos^2\beta = n^2$ Hence, the correct answer is n 2 .
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