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Question : If $\tan \alpha=\frac{1}{\sqrt{3}}$ and $\tan \beta=\sqrt{3}$ then what is the value of $\cos (\alpha+\beta)$?

Option 1: 0.2

Option 2: 0

Option 3: 0.5

Option 4: 1


Team Careers360 22nd Jan, 2024
Answer (1)
Team Careers360 24th Jan, 2024

Correct Answer: 0


Solution : $\tan \alpha=\frac{1}{\sqrt{3}}$
⇒ $\alpha = 30^{\circ}$
$\tan \beta=\sqrt{3}$
⇒ $ \beta = 60^{\circ}$
So, $\cos (\alpha+\beta)$
= $\cos (30^{\circ}+60^{\circ})$
= $\cos (90^{\circ}) = 0$
Hence, the correct answer is 0.

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