Question : If $\frac{b}{a}=0.7$, find the value of $\frac{a–b}{a+b}+\frac{11}{34}$.
Option 1: 0.2
Option 2: 1
Option 3: 0.5
Option 4: 0.3
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 0.5
Solution : Given: The value of the ratio $\frac{b}{a}=0.7$. The value of the expression $\frac{a–b}{a+b}+\frac{11}{34}$ is given as, $=\frac{1–\frac{b}{a}}{1+\frac{b}{a}}+\frac{11}{34}$ Substitute the value of $\frac{b}{a}=0.7$ in the above expression, $=\frac{1–0.7}{1+0.7}+\frac{11}{34}$ $=\frac{0.3}{1.7}+\frac{11}{34}$ $=0.17+0.33=0.5$ Hence, the correct answer is 0.5.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : The value of $\frac{0.7× 0.7× 0.7+0.3 × 0.3 × 0.3}{0.7 × 0.7-0.7× 0.3+0.3 × 0.3}$ is_____.
Question : What is the value of $\frac{(1.2)^{3} + (0.8)^{3} + (0.7)^{3} – 2.016}{(1.35)[(1.2)^{2} + (0.8)^{2} + (0.7)^{2} – 0.96 – 0.84 – 0.56]}?$
Question : If $\frac{21\cos A+3\sin A}{3\cos A+4\sin A}=2$, then find the value of cot A.
Question : If $\frac{a}{b} = \frac{7}{6}$, find the value of the expression $\frac{6a + 13b}{6a – 13b}$.
Question : Find the exact value of $\cos 120°$.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile