if for an ideal gas the ratio of pressure and volume is constant and is equal to 1 atm L-1 the molar heat capacity at constant pressure would be
Hello Candidate,
In the given question is mentioned that the ratio of pressure to volume is equal to 1. So here's the solution-
PV/V 2 = nRT/ V2
P/V =1⇒P=V
So, PV=RT
PdV+VdP=RdT
2pdV=RdT
pdV= 2 RdT
dq=C p dT; dV=C v dT
dq=dV+pdV
dq=C v dT + 2 RdT
dq=( 2/ 3 R + 2 R )dT
dq=2RdT
C p =2R