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if I want to get a seat in cse at suratkal NIT HOW MUCH PERCENTILE SHOULD I HAVE TO SCORE?


Amar Thakur 30th Mar, 2020
Answers (2)
KUNAL LANJEWAR 30th Mar, 2020

Hello,

Given below are the year wise opening and closing cutoff ranks for General Category students of NIT Surathkal for CSE Branch for JEE Mains Examination :

  • JEE Mains 2019 : Opening Rank = 623
  • JEE Mains 2018 : Opening Rank = 928 & Closing Rank = 3928
  • JEE Mains 2017 : Opening Rank = 666 & Closing Rank = 2940
  • JEE Mains 2016 : Opening Rank = 266 & Closing Rank = 1246

As NIT Surathkal is one of the best NITs to pursue CSE course, the cutoff percentile is very high every year. For getting this college, one needs to score a minimum percentile of 99 in JEE Mains Examination.

Best Wishes.

1 Comment
Comments (1)
30th Mar, 2020
what should be the minimum score then in this situation
Reply
S. Saha Student Expert 30th Mar, 2020
Going by previous year cutoffs, to get CSE in NIT Surathkal, through all India Quota you need a rank under 2000. Last year the cutoff was 2156.
For home state quota, last year the cutoff was around 3561. Now this is previous year's data and cutoffs change every year. So you have to score at least 99.8 percentile in Jee Main.
http://engineering.careers360.com/articles/jee-main-cutoff-for-nit-surathkal
Jee main april session is knocking at the door. Prepare with our jee main Knockout series-
http://learn.careers360.com/knockout-jee-main-april/
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