Question : If $x$ is the mean proportional between 12.8 and 64.8, then the value of $x$ is:
Option 1: 32
Option 2: 34
Option 3: 28.8
Option 4: 26.4
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Correct Answer: 28.8
Solution : According to the question, $c^2 = ab$ where $c$ is the mean proportion of $a$ and $b$. Now, the mean proportion of 12.8 and 64.8 $x=\sqrt{12.8 \times 64.8}$ $=\sqrt{16 \times 0.8\times 0.8 \times 81}$ $=4 \times 0.8 \times 9$ $x=28.8$ Hence, the correct answer is 28.8.
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