Question : If (sin $\alpha$ + cosec $\alpha$)2 + (cos $\alpha$ + sec $\alpha$)2 = k + tan2 $\alpha$ + cot2 $\alpha$, then the value of k is:
Option 1: 1
Option 2: 7
Option 3: 3
Option 4: 5
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Correct Answer: 7
Solution : (sin $\alpha$ + cosec $\alpha$) 2 + (cos $\alpha$ + sec $\alpha$) 2 = k + tan 2 $\alpha$ + cot 2 $\alpha$ Taking the left-hand side of the expression, we get, (sin $\alpha$ + cosec $\alpha$) 2 + (cos $\alpha$ + sec $\alpha$) 2 = sin 2 $\alpha$ + cosec 2 $\alpha$ + 2sin $\alpha$cosec $\alpha$ + cos 2 $\alpha$ + sec 2 $\alpha$ + 2cos $\alpha$sec $\alpha$ = (sin 2 $\alpha$ + cos 2 $\alpha$) + cosec 2 $\alpha$ + 2 + sec 2 $\alpha$ + 2 We know that sin 2 $\alpha$ + cos 2 $\alpha$ = 1. = 5 + cosec 2 $\alpha$ + sec 2 $\alpha$ = 5 + (1 + cot 2 $\alpha$) + (1 + tan 2 $\alpha$) = 7 + tan 2 $\alpha$ + cot 2 $\alpha$ Comparing it with the right-hand side, we get, k = 7 Hence, the correct answer is 7.
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