if the de Broglie wavelength of the electron in nth Bohr orbit are hydrogenic atom is equal to 1.5 pi a there the value of n by z
Hii,
The solution of this is:
2πr = nλ
2π ao * n^2/z = n*1.5*π ao
n/z = 0.75
Hope this helps.
Hii,
The solution of this is:
2πr = nλ
2π ao * n^2/z = n*1.5*π ao
n/z = 0.75
Hope this helps.
Followers ()
Select your reason of reporting
Select your reason of reporting
We endeavor to keep you informed and help you choose the right Career path. Sign in and access our resources on Exams, Study Material, Counseling, Colleges etc.
When you look back in life , this app would have played a huge role in laying the foundation of your career decisions.
Found everything I wanted and it solved all of my queries for which I was searching a lot....very helpful site. A must visit.... kudos to the team!
No need to find colleges in other sites, this is the best site in India to know about any colleges in India.