The de Brogile wavelength of an electron in the 4th Bohr orbit is
Answer (1)
17th May, 2020
Hello aspirant,
According to Bohr's postulates, the radii of the nth and the first orbits are given by:
rn=n2r1nλn=2πrn ⇒ λn=2nπr1.
Now, for n=4, we have:
λ4=8πr1=8πr.
Thank you.
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