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    The de Brogile wavelength of an electron in the 4th Bohr orbit is

    ADITYA PRATAP SINGH 17th May, 2020
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    Answer (1)
    Devanshi Adhikari 17th May, 2020

    Hello aspirant,

    According to Bohr's postulates, the radii of the nth and the first orbits are given by:

    rn=n2r1nλn=2πrn ⇒ λn=2nπr1.

    Now, for n=4, we have:

    λ4=8πr1=8πr.

    Thank you.


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