Question : If the inner radius of a hemispherical bowl is 5 cm and its thickness is 0.25 cm, find the volume of the material required to make the bowl. (Use $\pi = \frac{22}{7}$)
(Rounded up to two decimal places).
Option 1: 34 cm3
Option 2: 44 cm3
Option 3: 45.34 cm3
Option 4: 41.28 cm3
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Correct Answer: 41.28 cm 3
Solution :
Volume of the hemispherical bowl = $\frac{2}{3} × \pi × (R^{3} - r^{3})$
Where, $r$ is the inner radius of the bowl = 5 cm
And, $R$ is the outer radius of the bowl = (5 + 0.25) = 5.25 cm
So, the volume $=\frac{2}{3} × \frac{22}{7} × [(5.25^{3}) - (5)^{3}]$
$=\frac{44}{21} × 19.70$
$= 41.28$ cm
3
Hence, the correct answer is 41.28 cm
3
.
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