Question : Steel is used to make a hemispherical bowl that is 0.37 cm thick. The bowl's inner radius is 6 cm. Find the bowl's outside curved surface area (take $\pi=\frac{22}{7}$).
Option 1: 532 cm2
Option 2: 255.0548 cm2
Option 3: 484 cm2
Option 4: 523.4107 cm2
Correct Answer: 255.0548 cm 2
Solution :
Given: Steel is used to make a hemispherical bowl that is 0.37 cm thick.
The bowl's inner radius is 6 cm.
According to the formula,
⇒ Outer radius = 6 + 0.37 = 6.37 cm
$\therefore$ Curved surface area = 2 × 227 × 6.37 × 6.37 = 255.0548 cm
2
Hence, the correct answer is 255.0548 cm
2
.
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