Question : If $0°<\theta<90°$, the value of $\sin\theta+\cos\theta$ is:
Option 1: Equal to 1
Option 2: Greater than 1
Option 3: Less than 1
Option 4: Equal to 2
Answer (1)
24th Jan, 2024
Correct Answer: Greater than 1
Solution :
$\sin\theta+\cos\theta$ where $0°<\theta<90°$
Putting the value of $\theta=45°$, we have,
$\sin 45°+\cos45°=\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}$
⇒ $\sin 45°+\cos45° =\frac{2}{\sqrt{2}}=\sqrt{2}$
Here, $\sqrt{2}=1.414>1$
Hence, the correct answer is greater than 1.
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