Question : If $ an A=\frac{2}{3}$, then find $\sin A$.
Option 1: $\frac{1}{3}$
Option 2: $\frac{2}{\sqrt{13}}$
Option 3: $\frac{2}{3}$
Option 4: $\frac{3}{\sqrt{13}}$

Question

Question : If $ an A=\frac{2}{3}$, then find $\sin A$.

Option 1: $\frac{1}{3}$

Option 2: $\frac{2}{\sqrt{13}}$

Option 3: $\frac{2}{3}$

Option 4: $\frac{3}{\sqrt{13}}$

Team Careers360 · Accepted Answer

Correct Answer: $\frac{2}{\sqrt{13}}$

Solution : Given, $ an A=\frac{2}{3}$
Let perpendicular and base be 2 and 3 units.
Now, the hypotenuse $= \sqrt{2^2+3^2} = \sqrt{13}$ units
So, $\sin A = \frac{ ext{perpendicular}}{ ext{hypotenuse}}=\frac{2}{\sqrt{13}}$
Hence, the correct answer is $\frac{2}{\sqrt{13}}$.

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Question : If $\tan A=\frac{2}{3}$, then find $\sin A$.Option 1: $\frac{1}{3}$Option 2: $\frac{2}{\sqrt{13}}$Option 3: $\frac{2}{3}$Option 4: $\frac{3}{\sqrt{13}}$

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Question : If $\tan A=\frac{2}{3}$, then find $\sin A$.
Option 1: $\frac{1}{3}$
Option 2: $\frac{2}{\sqrt{13}}$
Option 3: $\frac{2}{3}$
Option 4: $\frac{3}{\sqrt{13}}$