3 Views

Question : If $x=\frac{1}{x-3},(x>0)$, then the value of $x+\frac{1}{x}$ is:

Option 1: $\sqrt{11}$

Option 2: $\sqrt{17}$

Option 3: $\sqrt{15}$

Option 4: $\sqrt{13}$


Team Careers360 24th Jan, 2024
Answer (1)
Team Careers360 25th Jan, 2024

Correct Answer: $\sqrt{13}$


Solution : Given: $x=\frac{1}{x-3},(x>0)$
Or, $x^2-3x-1=0$
Or, $x=\frac{3\pm\sqrt{13}}{2}$
So, $x = \frac{3+\sqrt{13}}{2}$
Now, $x+\frac{1}x = \frac{3+\sqrt{13}}{2}+\frac{2}{3+\sqrt{13}}$
Rationalising,
= $\frac{3+\sqrt{13}}{2}+\frac{2}{3+\sqrt{13}}\times \frac{3-\sqrt{13}}{3-\sqrt{13}}$
= $\frac{3+\sqrt{13}}{2}+2\times \frac{3-\sqrt{13}}{-4}$
= $\sqrt13$
Hence, the correct answer is $\sqrt{13}$.

SSC CGL Complete Guide

Candidates can download this ebook to know all about SSC CGL.

Download EBook

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
GRE ® Registrations 2024
Apply
Apply for GRE® Test now & save 10% with ApplyShop Gift Card | World's most used Admission Test for Graduate & Professional Schools
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books