Question : If $x+y+z=0$, then the value of $\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}$ is:
Option 1: 3
Option 2: 1
Option 3: 0
Option 4: 2
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 3
Solution : $\frac{x^2}{y z}+\frac{y^2}{z x}+\frac{z^2}{x y}=\frac{x^3+y^3+z^3}{xyz}$ Use identity: If $a+b+c=0$, then $a^3+b^3+c^3=3abc$. Given, $x+y+z=0$ So, $\frac{x^2}{y z}+\frac{y^2}{z x}+\frac{z^2}{x y}=\frac{3xyz}{xyz}$ = 3 Hence, the correct answer is 3.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : If $\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}=3$, then what is the value of $(x+y+z)^3$?
Question : If $x+y+z=0$, then what is the value of $\frac{x^2}{yz}+\frac{y^2}{xz}+\frac{z^2}{xy}$?
Question : If $xy+yz+zx=1$ , then the value of $\frac{1\:+\:y^2}{(x\:+\:y)(y\:+\:z)}$ is:
Question : If $x+y+z=0$, then what is the value of $\frac{x^2}{(y z)}+\frac{y^2}{(x z)}+\frac{z^2}{(x y)}$?
Question : If $x+y+z = 22$ and $xy+yz+zx = 35$, then what is the value of $\small (x-y)^{2}+(y-z)^{2}+(z-x)^{2}$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile