Question : If $x+y+z=0$, then the value of $\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}$ is:
Option 1: 3
Option 2: 1
Option 3: 0
Option 4: 2
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Correct Answer: 3
Solution : $\frac{x^2}{y z}+\frac{y^2}{z x}+\frac{z^2}{x y}=\frac{x^3+y^3+z^3}{xyz}$ Use identity: If $a+b+c=0$, then $a^3+b^3+c^3=3abc$. Given, $x+y+z=0$ So, $\frac{x^2}{y z}+\frac{y^2}{z x}+\frac{z^2}{x y}=\frac{3xyz}{xyz}$ = 3 Hence, the correct answer is 3.
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