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Question : If $(x-5)^2+(y-2)^2+(z-9)^2=0$, then value of $(x+y-z)$ is:

Option 1: 16

Option 2: –1

Option 3: –2

Option 4: 12


Team Careers360 18th Jan, 2024
Answer (1)
Team Careers360 21st Jan, 2024

Correct Answer: –2


Solution : Given:
$(x-5)^2+(y-2)^2+(z-9)^2=0$
So, $x=5, y=2, z=9$
Therefore, $x+y-z = (5+2-9) = -2$
Hence, the correct answer is –2.

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