Question : If $\frac{3x-1}{x}+\frac{5y-1}{y}+\frac{7z-1}{z}=0$, what is the value of $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}?$
Option 1: –3
Option 2: 0
Option 3: 15
Option 4: 21
Answer (1)
23rd Jan, 2024
Correct Answer: 15
Solution :
Given:
$\frac{3x-1}{x}+\frac{5y-1}{y}+\frac{7z-1}{z}=0$
⇒$3-\frac{1}{x}+5-\frac{1}{y}+7-\frac{1}{z}=0$
⇒$\frac{1}{x} + \frac{1}{y}+\frac{1}{z}= 3+5+7=15$
Hence, the correct answer is 15.
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