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    • Question : If $\frac{3x-1}{x}+\frac{5y-1}{y}+\frac{7z-1}{z}=0$, what is the value of
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    Question : If $\frac{3x-1}{x}+\frac{5y-1}{y}+\frac{7z-1}{z}=0$, what is the value of $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}?$

    Option 1: –3

    Option 2: 0

    Option 3: 15

    Option 4: 21

    Team Careers360 17th Jan, 2024
    Answer
    Answer (1)
    Team Careers360 23rd Jan, 2024

    Correct Answer: 15


    Solution : Given:
    $\frac{3x-1}{x}+\frac{5y-1}{y}+\frac{7z-1}{z}=0$
    ⇒$3-\frac{1}{x}+5-\frac{1}{y}+7-\frac{1}{z}=0$
    ⇒$\frac{1}{x} + \frac{1}{y}+\frac{1}{z}= 3+5+7=15$
    Hence, the correct answer is 15.

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