Question : In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm. What is the radius (in cm) of the circumcircle of $\triangle$ ABC?
Option 1: 12.5
Option 2: 13
Option 3: 25
Option 4: 26
Correct Answer: 13
Solution :
In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm
AB
2
= AC
2
+ BC
2
$AB = \sqrt{24^2 + 10^2} = \sqrt{576+100} = \sqrt{676} = 26$ cm
Circumradius of $\triangle ABC = \frac{AB}{2} = \frac{26}{2} = 13$ cm
Hence, the correct answer is 13.
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