Question : In an examination, a candidate had to sit for three papers, A, B, and C. The candidate secured 75% marks in Paper A, 80% marks in Paper B, and 60% marks in Paper C. If the weightage assigned to Papers A, B, and C were 40%, 50%, and 10%, respectively, find the weighted percentage of marks obtained by the candidate, when all the three papers were taken together.
Option 1: 77%
Option 2: 74%
Option 3: 72%
Option 4: 76%
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Correct Answer: 76%
Solution :
Let the maximum mark of each paper be 100.
Mark obtained in paper A = 75% 0f 100 = 75
Mark obtained in paper B = 80% 0f 100 = 80
Mark obtained in paper C = 60% 0f 100 = 60
If the weightage assigned to Papers A, B, and C were 40%, 50%, and 10%, respectively.
Total mark = $\frac{75\times 40}{100} + \frac{80\times 50}{100}+\frac{60\times 10}{100}$
= $30 + 40 + 6$
= $76$
Percentage of mark = $\frac{76}{100}$ × 100% = 76%
Hence, the correct answer is 76%.
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