Question : In an examination, the average marks of a student per paper were 71. If he had obtained 35 more marks in sciences; 11 more marks in history and 4 more marks in computer science, his average marks per paper would have been 76. How many papers were there in the examination?
Option 1: 10
Option 2: 12
Option 3: 18
Option 4: 15
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Correct Answer: 10
Solution :
Average marks of a student per paper = 71
Let $n$ be the number of papers.
Total marks scored = $71n$
New average = 76
New total = $76n$
⇒ $71n + 35 + 11 + 4 = 76n$
⇒ $5n = 50$
⇒ $n = 10$
Hence, the correct answer is 10.
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