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hello,
You can solve the numerical like this:
- Molecular weight of Fe2O3 = (56×2) + (16×3) = 160g
- Molar mass of Fe in 1 mole of Fe2O3 = 56×2=112g
Therefore %age composition of Fe in Fe2O3= molarmass of Fe ÷ Molecular weight of Fe2O3 ×100 =160112 × 100 = 70%
Hope this helped !!
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