integration of a power x . e power x dx
Answer (1)
14th Dec, 2020
Dear student,
We will solve this integration using ' By Parts '.
Now take a^x as the 1st function and e^x as the 2nd function, according to the ILATE Rule.
Now We use, intg(1*2) = 1.intg(2) - intg.{diff.(1)intg(2)}
Let, I be the answer of this integration then,
I = a^x.e^x - intg[a^x. log(a). e^x] now we can write it as
I = a^x.e^x - log(a). I
so clearly I = a^x.e^x/ 1+log(a)
Hope this helps.
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