kinetic and potential energy of electron present in third bohrs orbit of hydrogen atom
Answer (1)
8th Nov, 2020
Third Bohe orbit corresponds to principle quantum number, n = 3.
Now, energy of an electron in n = n is En= - 13.6/ n^2 eV for hydrogen atom.
Now, in Bohr's theory we come across the result:En= (1/2) ( potential energy).
Therefore, (1/2)(potential energy )=-(13.6/9)eV.
Therefore, potential energy =-27.2/9 eV……………..(1)
Now, kinetic energy K = total energy - potential energy
Then, K=-13.6/9-(-27.2/9)=13.6/9 eV.
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