Question : Let D and E be two points on the side BC of $\triangle ABC$ such that AD = AE and $\angle BAD = \angle EAC$. If AB=(3x+1) cm, BD = 9 cm, AC=34 cm and EC = (y + 1) cm, then the value of (x + y) is:
Option 1: 19
Option 2: 16
Option 3: 17
Option 4: 20
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Correct Answer: 19
Solution : If two sides of a triangle are equal, then the angles opposite to these sides are equal. An exterior angle of a triangle is equal to the sum of the two opposite interior angles. Angle - Angle (AA) property:- In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar. $\angle$ BAD = $\angle$ EAC (Given in the question) ----(1) In $\triangle$ ADE ⇒ AD = AE (Given in the question) ⇒ $\angle$ ADE = $\angle$ AED (angles of an isosceles triangles) ----(2) So $\angle$ ADB = $\angle$ AEC (Supplementary angles of $\angle$ ADE and $\angle$ AED) Considering $\triangle$ABD and $\triangle$AEC ⇒ $\angle$ ADB = $\angle$ AEC (Equal angles) $\angle$ BAD = $\angle$ EAC (Given in the question) AD = AE (Given in the question) By the Property of triangles ASA, we can conclude $\triangle$ABD ~ $\triangle$ACE So, $\frac{\text{AB}}{\text{AC}} = \frac{\text{BD}}{\text{CE}} = \frac{\text{AD}}{\text{AE}}$ $\frac{3\text{x}+1}{34} = \frac{9}{\text{y}+1} = 1$ ---(3) Solving the above equation we get 3x + 1 = 34 ⇒ x = 11 Similarly, y + 1 = 9 ⇒ y = 8 The value of (x + y) = 11 + 8 = 19 $\therefore$ The value of (x + y) is 19 cm. Hence, the correct answer is 19 cm.
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