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Limit xam tends to 2 [x-2/x^2-x-1/x^3-3x^2+2x]


Priyanshu Saurabh 3rd Apr, 2019
Answers (2)
Ashutosh katkam 6th Apr, 2019
Hellooooo.......



Here below i am providing solution to your problem by expecting your question be like ....



Lim x-->2   (x-2)(x^2-x-1)/(x^3-3x^2+2x)



By applying L hospital rule differentiating on numerator and denominator we get



Limx-->2  (x-2)(2x-1)+(x^2-x-1)(1)/(3x^2-6x+2)

By substituting we get

1/2

As solution...

If your question was something different mention below in comment box....

Thank you..












Billa Nikhil reddy 6th Apr, 2019


Hello

please write the question properly using brackets.

And divisions bis thrice.  Give it in a p/q format.

Thank you



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