Question : Meenu is 38 years old. Her daughter is 8 years old. In how many years will Meenu be double her daughter's age?
Option 1: 22
Option 2: 25
Option 3: 20
Option 4: 24
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Correct Answer: 22
Solution :
Meenu's present age = 38 years
Daughter's present age = 8 years
Let be the after $x$ number of years from the present year for Meenu's age be twice of that of her daughter's age.
$\therefore$ $38+x=2(8+x)$
⇒ $38-16=x$
⇒ $x=22$ years
Hence, the correct answer is 22.
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