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Minimum marks I should take in JEE MAIN 2020 to get seat in NITK SURATKAL for CSE BRANCH ,my category OBC .


Bhimanna Bhima 1st Jun, 2019
Answers (2)
Jaswanth Vemula 1st Jun, 2019

Hello,

Here are the cut off ranks of NIT Suratkal of 2019:
Computer Science and Engineering
General category
Home state
Openning rank:928
Closing rank:3928
Other state
OR:278
CR:1767
OBC NCL
Home state
Openning rank:
877
Closing rank:
2237
Other state
OR:334
CR:663
SC
Home state
Openning rank:170
Closing rank:889
Other state
OR:181
CR:273
ST
Home state
Openning rank:228
Closing rank:344
Other state:
OR:116
CR:123
You can see the ranks and also for more information visit https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-surathkal

Thank you.

MANAS BHATNAGAR 1st Jun, 2019

HELLO BHIMANNA!

DON'T JUST AIM FOR MINIMUM MARKS GO FOR MAXIMUM EFFORT THAT YOU CAN PUT THAT WOULD EVENTUALLY FETCH YOU GOOD MARKS. AND I WOULD SUGGEST YOY TO SCORE A 250+ IN JEE MAINS THAT WILL GET YOU A BRANCH OF YOUR CHOICE ANYWHERE.FOR MORE DETAILED RANK CUTOFF PLEASE VISIT https://engineering.careers360.com/articles/jee-main-cutoff

HOPE THIS HELPS!

ALL THE BEST!

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