my daughter scored 96.67 in jee mains 2020 .she is also EWS candidate. which rank we will expect?
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It’s difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank
100 - your total percentile score is the percentage of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100
I have calculated your rank using above formula as 28938.you can see in which college you can get admission using career360 college predictor i have attched the link below
It’s difficult to tell exact qualifying marks for jee advanced eligibility but if you are getting more than 85 percentile score then you have decent chances to qualify for jee advanced
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 28938 . Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100.
You haven't mentioned the State your daughter belongs to because with her percentile, she has decent chances at NIT of her home state. And she has decent chances to qualify for JEE Advanced because any percentile above 85 at this point in time is expected to be qualifying percentile for JEE Advanced. So please do help us with the State your daughter belongs. Or you can as well check the cut offs of various NITs of previous years. Now cut offs do change every year depending on various factors but this will give you a fair idea of the trend. https://engineering.careers360.com/articles/jee-main-cutoff
Now to predict colleges, please use our college predictor:
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