my percentile in JEE MAINS 2020 Paper 2 is 98.8944435 can I get admission in SPA Delhi or can u give any other advice?
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You can calculate your rank in JEE Main Paper 2 using the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 2 (Jan) are around 112679, your rank will be around 1250. However as the no. of students in April changes, your rank will change according to that.
With this rank, there are some chances of getting admission into SPA Delhi. However, you may also apply to some NIT colleges which offer Architecture branch. To check the cutoffs for NITs which offer Architecture branch, you can use the following link:
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
However, to get the list of all Institutes which you may get with this rank, kindly use the college predictor through the link given:
For more information regarding counseling, cutoffs, etc.. you can use the B.Tech companion from the link given below:
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