Hello..

For your percentile your predicted rank will be around 35,600.

The approximate rank formula is (100-percentile)*874469/100.

If we apply the formula with your percentile we will get the predicted rank .

If you compare your predicted rank with the closing ranks of mechanical nit Raipur you will get to know the chances of getting the seat.

For more details visit the link:

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-nit-raipur/amp

All the best

Thank you..

Dear Ayush,

A big congratulation.You got too good Percentile in JEE main..

As you know at this time it is very dificult to say about your rank or anything.

but you can know this by using the link given below

https://engineering.careers360.com/jee-main-rank-predictor

for this you will need to give some of your informations like,

• your JEE main Application No.
• DOB
• Your JEE main NTA percentile
• category
• Date of Exam
• 12th passing year

In the above link there  is rank predictor given .if you will fill that, then you will be eligible to see your predicted rank.

and if  you get rank in JEE main about or above 93112 , then you will definatly get NIT raipur.

for more information please visit

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-raipur

All the very best Ayush.

thankyou so much.

for more Queries please be in touch with us.

Hello Ayush



Your percentile score is quite good.!



The final cutoff percentile along with the ranks will be released by NTA after the April session exam. The different NITs will also declare their admission cutoffs based on the final result (percentile+rank) by NTA.

So you will have to wait for now.

Your rank comes around 35K-36K based on the below given formula:

(100 - your percentile) * (874469/100)

Here, 874469 is the total number of students who appeared in the January session of JEE Mains.

The rank may vary with the actual one depending on the number of students appearing for the April session.

Well according to (2018) last year, the closing ranks for NIT-Raipur were 93112 (homestate) and 32479 (other state).

As per your estimated rank there are 50-50 chances for you to get admission there. Once the cutoff percentile is released- you'll get the fair idea of admission anywhere.

Hope for the best.!



Good Luck.!

NIT Raipur

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