Question : O is the centre of the circle and AB is the tangent to it touching at B. If OB = 3 cm and OA = 5 cm, then the measure of AB (in cm) is:
Option 1: $\sqrt{34}$
Option 2: $2$
Option 3: $8$
Option 4: $4$
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Correct Answer: $4$
Solution :
Given: O is the centre of the circle and AB is tangent to it touching at B.
OB = 3 cm and OA = 5 cm
Using the Pythagoras theorem, from $\triangle$AOB, we get,
AB
2
= OA
2
– OB
2
$\therefore$ AB $=\sqrt{5^2-3^2}=\sqrt{16}=4$ cm
Hence, the correct answer is $4$.
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