Question : One liquid contains 20% of acid the other liquid contains 30% of acid. A can is filled with 7 parts of the first liquid and 3 parts of the second liquid. The percentage of the acid in the new mixture is:
Option 1: 13%
Option 2: 30%
Option 3: 14%
Option 4: 23%
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Correct Answer: 23%
Solution : Let the first liquid be $A$ and the second liquid be $B$. The first liquid $A$ contains 20% acid, and the second liquid $B$ contains 30% acid ⇒ The total parts in the mixture are 7 + 3 = 10 So, the acid percentage in new mixture = $\frac{\text{Percentage of acid in A×Parts of A}}{\text{Total Parts}}$+$\frac{\text{Percentage of acid in B×Parts of B}}{\text{Total Parts}}$ = $\frac{20×7}{10}+\frac{30×3}{10}$ = $\frac{140}{10}+\frac{90}{10}$ = ${14}+{9}$ = ${23}$% Hence, the correct answer is 23%.
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