11 Views

Question : One liquid contains 20% of acid the other liquid contains 30% of acid. A can is filled with 7 parts of the first liquid and 3 parts of the second liquid. The percentage of the acid in the new mixture is:

Option 1: 13%

Option 2: 30%

Option 3: 14%

Option 4: 23%


Team Careers360 19th Jan, 2024
Answer (1)
Team Careers360 22nd Jan, 2024

Correct Answer: 23%


Solution : Let the first liquid be $A$ and the second liquid be $B$.
The first liquid $A$ contains 20% acid, and the second liquid $B$ contains 30% acid
⇒ The total parts in the mixture are 7 + 3 = 10
So, the acid percentage in new mixture = $\frac{\text{Percentage of acid in A×Parts of A}}{\text{Total Parts}}$+$\frac{\text{Percentage of acid in B×Parts of B}}{\text{Total Parts}}$
= $\frac{20×7}{10}+\frac{30×3}{10}$
= $\frac{140}{10}+\frac{90}{10}$
= ${14}+{9}$
= ${23}$%
Hence, the correct answer is 23%.

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books