Question : PQR is an equilateral triangle and the centroid of triangle PQR is point A. If the side of the triangle is 12 cm, then what is the length of PA?
Option 1: $4 \sqrt{3}$ cm
Option 2: $8 \sqrt{3}$ cm
Option 3: $2 \sqrt{3}$ cm
Option 4: $\sqrt{3}$ cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: $4 \sqrt{3}$ cm
Solution :
Given: PQR is an equilateral triangle and the centroid of triangle PQR is point A.
The side of the triangle is 12 cm.
The equilateral triangle circumradius = $\frac{\text{side}}{\sqrt3}$.
The equilateral triangle's centres are all located at the same point. Whether it's a centroid, incentre, orthocentre, or circumcentre.
The length of PA = $\frac{PQ}{\sqrt3}$.
$=\frac{12}{\sqrt3}=4\sqrt3$ cm
Hence, the correct answer is $4\sqrt3$ cm.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
