74 Views

prove that (sin3x +sinx ) sinx+(cos3x-cosx) cosx =0


Haneef khan 2nd Jan, 2021
Answer (1)
Anuj More 2nd Jan, 2021

Dear Aspirant,

Kindly know all the formulas for trigonometry,

We know that,

sin A + sin B = 2*[sin(A+B)/2 * cos(A-B)/2]

& Similarly,

cos A - cos B = -2*[sin(A+B)/2 * sin(A-B)/2]

So using these formulas,

= (sin3x + sinx) * sinx + (cos3x - cosx) * cosx

= (2sin2xcosx) * sinx - (2sin2xsinx) * cosx

After multiplying the terms, you'll get 0 as the final result.

Thanks for visiting this site, hope it helped you.


Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
TAPMI MBA 2025 | Technology M...
Apply
MBA Admission Open in Technology Management and AI & Data Science | NAAC A++ | Institution of Eminence | Assured Scholarships
Sanskriti University LLM Admi...
Apply
Best innovation and research-driven university of Uttar Pradesh
Maya Devi University LLM admi...
Apply
43.6 LPA Highest Package | 5.48 LPA Average Package | 150+ Courses in UG, PG, Ph.D
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Shri Khushal Das University L...
Apply
Approved by UGC | Robust Placement Assistance
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books