Hello candidate,

The formula for EMF of a cell in a Galvanic reaction is given by

EMF= E0- 0.059/n×{log Kc}. In this question, the value of E0= -0.13- (-.76)= 0.63 and the value of n=2. Kc equals to 0.2/0.1=2.

Hence putting all the values in the equation, we find the value of EMF = 0.63-.059/2×{log2} = 0.62 Volts.

Hope that this answer was helpful for you!!

Have a good day.