132 Views

Question of physics of Law of motion


arvy 20th Dec, 2018
Answer (1)
Vikas gehlot 20th Dec, 2018

Since the bomb was initially at rest and it explodes into internal force therefore the total net external force on the bomb is zero and hence linear momentum is conserved.

Therefore let p be the momentum

Then

M+xi-2xj=0

Therefore

M= 2xj-xi

Therefore magnitude of m is X sq root of 5.



1 Comment
Comments (1)
20th Dec, 2018
your answer is right sir thank you
Reply

Related Questions

JSS University Noida Admissio...
Apply
170+ Recruiters Including Samsung, Zomato, LG, Adobe and many more | Highest CTC 47 LPA
Starex University B.Sc Admiss...
Apply
Ranked #12 in University category & #1 in North India by IIRF 2024 | Collaboration with IBM- ICE for Hi-Tech Programs
Amity University | B.Sc Admis...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
SRM University, Sonepat B.Sc ...
Apply
Upto 100% waiver in tuition fees for limited seats
Guru Kashi University B.Sc Ad...
Apply
NAAC A++ Accredited
GMAT™ Exam
Apply
Select test center appointment | Scores valid for 5 Years | Multiple Attempts | Round 1 Applications Closing Soon
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books