Question : Steel is used to make a hemispherical bowl that is 0.37 cm thick. The bowl's inner radius is 6 cm. Find the bowl's outside curved surface area (take $\pi=\frac{22}{7}$).
Option 1: 532 cm2
Option 2: 255.0548 cm2
Option 3: 484 cm2
Option 4: 523.4107 cm2
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Correct Answer: 255.0548 cm 2
Solution : Given: Steel is used to make a hemispherical bowl that is 0.37 cm thick. The bowl's inner radius is 6 cm. According to the formula, ⇒ Outer radius = 6 + 0.37 = 6.37 cm $\therefore$ Curved surface area = 2 × 227 × 6.37 × 6.37 = 255.0548 cm 2 Hence, the correct answer is 255.0548 cm 2 .
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Question : If the inner radius of a hemispherical bowl is 5 cm and its thickness is 0.25 cm, find the volume of the material required to make the bowl. (Use $\pi = \frac{22}{7}$) (Rounded up to two decimal places).
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Question : If the slant height of a cone is 60 cm and the radius of its base is 21 cm, then find its curved surface area is? (use $\pi=\frac{22}{7}$)
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