Question : In $\triangle$ABC, $\angle$A = 90°, AD$\perp$BC and AD = BD = 2 cm. The length of CD is:

Question : Suppose $\triangle A B C$ be a right-angled triangle where $\angle A=90^{\circ}$ and $A D \perp B C$. If area $(\triangle A B C)$ $=80 \mathrm{~cm}^2$ and $BC=16$ cm, then the length of $AD$ is:

Question : ABC is an isosceles triangle and $\overline{AB} = \overline{AC} = 2a$ units and $\overline{BC} = a$ unit. Draw $\overline{AD} \perp \overline{BC}$, then find the length of $\overline{AD}$.

Question : In triangle ABC, $\angle$ B = 90°, and $\angle$C = 45°. If AC = $2 \sqrt{2}$ cm then the length of BC is:

Question : In a triangle ${ABC}, {AB}={AC}$ and the perimeter of $\triangle {ABC}$ is $8(2+\sqrt{2}) $ cm. If the length of ${BC}$ is $\sqrt{2}$ times the length of ${AB}$, then find the area of $\triangle {ABC}$.