Taking the RMS velocity of hydrogen moleculesat NTP as 1.84km/s, calculate the RMS velocity of oxygen molecule at NTP. Molecular weights of oxygen and hydrogen are 32 and 2 respectively.
Answer (1)
20th Apr, 2020
Hi,
rms velocity ofM2at11TP=V1=1.84km/s
as,V1=root(3RT/M1)(1)
M1=molar mass ofH2=0.002kg/moL
and that of oxygen(O2)
V2=root (3RT/M2)(2)
M2=0.032kg/moL
so dividing(1)(2),
V1/V2 = root(M2/M1)
V2=V1 root(M1/M2)
V2=1.84 x root(2/32)
V2= 0.46km/s
V2=1.84322=1.8441=0.46km/s
rms velocity ofM2at11TP=V1=1.84km/s
as,V1=root(3RT/M1)(1)
M1=molar mass ofH2=0.002kg/moL
and that of oxygen(O2)
V2=root (3RT/M2)(2)
M2=0.032kg/moL
so dividing(1)(2),
V1/V2 = root(M2/M1)
V2=V1 root(M1/M2)
V2=1.84 x root(2/32)
V2= 0.46km/s
V2=1.84322=1.8441=0.46km/s
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