target loses half of its velocity after penetrating 3cm. How much further it will penetrate before coming to rest, assuming that it faces constant resistance to motion? (Provide your answer in cm) [neglect gravity]
Answer (1)
9th Apr, 2020
Hello,
To solve this problem, we'll use the formula
v^2 - u^2 = 2as.
Here v is final velocity.
v is u/2 at distance s=3cm.
We have to find the value of a.
Substituting the values, we get:
a= -1 * (u^2 / 12). ----- Let this be equation 1.
In case 2, using the same formula,
now, initial velocity u is u/2. Final velocity v is 0.
a is substituted from eq. 1.
Hence we get, 0 - (u/2)^2 = 2 * s * (-u^2/12)
Therefore, s = 3cm. This is the distance the target travels before coming to rest.
Hope this helps.
Thanks.
Comments (0)
Related Questions
Trending Articles/News
CLAT Rank 7000-8000: The NLUs You Can Get Into
9 minutes ago
CLAT Rank 4000-5000: NLUs You Can Target!
17 minutes ago
