the angular velocity and amplitude of a simple pendulum is omega and A respectively at a displacement x if its KE is T and potential energy isU then the ratio of T to U is
Answer (1)
13th Apr, 2020
Hello,
We know that, for Simple Pendulum,
Kinetic Energy = T = [ m.ω^2 ( A^2 − x^2 ) ] / 2
Potential Energy = U = m.ω^2.x^2
Hence, Ratio of Kinetic Energy to the Potential Energy is,
T / U = ( A^2 - x^2 ) / x^2
i.e., T : U = ( A^2 - x^2 ) : x^2
Best Wishes.
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