Question : The area of the floor of a cubical room is 64 m2. The length of the longest rod that can be kept in the room is:
Option 1: $16 \sqrt{3} \mathrm{~m}$
Option 2: $4 \sqrt{3} \mathrm{~m}$
Option 3: $12 \sqrt{3} \mathrm{~m}$
Option 4: $8 \sqrt{3} \mathrm{~m}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: $8 \sqrt{3} \mathrm{~m}$
Solution :
Given: The area of the floor of a cubical room is 64 m
2
.
Let the sides of the room be $a$.
So, $a^2 = 64$
⇒ $a = 8\ \mathrm{m}$
The length of the longest rod = the diagonal of the cubical room = $a\sqrt3$
The length of the longest rod = $8 \times\sqrt3=8\sqrt3\ \mathrm{m}$
Hence, the correct answer is $8\sqrt3\ \mathrm{m}$.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
