Question : The area of the floor of a cubical room is 64 m2. The length of the longest rod that can be kept in the room is:
Option 1: $16 \sqrt{3} \mathrm{~m}$
Option 2: $4 \sqrt{3} \mathrm{~m}$
Option 3: $12 \sqrt{3} \mathrm{~m}$
Option 4: $8 \sqrt{3} \mathrm{~m}$
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Correct Answer: $8 \sqrt{3} \mathrm{~m}$
Solution : Given: The area of the floor of a cubical room is 64 m 2 . Let the sides of the room be $a$. So, $a^2 = 64$ ⇒ $a = 8\ \mathrm{m}$ The length of the longest rod = the diagonal of the cubical room = $a\sqrt3$ The length of the longest rod = $8 \times\sqrt3=8\sqrt3\ \mathrm{m}$ Hence, the correct answer is $8\sqrt3\ \mathrm{m}$.
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Question : Find the area of an equilateral triangle whose sides are 16 cm.
Question : If the side of an equilateral triangle is 16 cm, then what is its area?
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