133 Views

The circle passing through (-1,0)and touches y-axis at (0,2).So find the point which is passing through this?


Vindha 7th Sep, 2020
Answer (1)
Vineeth Wilson 7th Sep, 2020

Let (h,k) be center of circle.Circle touches the y-axis.
∴ Radius of circle =h
Equation of circle-
(x−h)2+(y−k)2=h2.....(1)Since the circle passes through (0,2)
Therefore,
h2+(2−k)2=h2
⇒(k−2)2=0
⇒k=2
Given that the circle also passes through (−1,0),
Therefore,
(−1−h)2+22=h2
h2+1+2h+4=h2
h=−25
Substituting the value of h and k in eqn(1), we get
(x+25)2+(y−2)2=(25)2
Now, we can find the point from which the circle passes.
As the point (4,0) satisfy the equation of circle.
Thus, the circle will also pass through the point (−4,0).
Hence the correct answer is (D)(−4,0).

Related Questions

UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC
SLAT 2025 - The Symbiosis Law...
Apply
Conducted by Symbiosis International (Deemed University) | Ranked #5 in Law by NIRF | Ranked #2 among best Pvt Universities by QS World Rankings
Jindal Global Law School Admi...
Apply
Ranked #1 Law School in India & South Asia by QS- World University Rankings | Merit cum means scholarships
Symbiosis Law School Pune Adm...
Apply
NAAC A++ Accredited | Ranked #5 by NIRF
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC
ISBR Business School PGDM Adm...
Apply
Ranked as Platinum Institute by AICTE for 5 years in a row | Awarded Best Business School of the Year
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books