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The de Brogile wavelength of an electron in the 4th Bohr orbit is


ADITYA PRATAP SINGH 17th May, 2020
Answer (1)
Devanshi Adhikari 17th May, 2020

Hello aspirant,

According to Bohr's postulates, the radii of the nth and the first orbits are given by:

rn=n2r1nλn=2πrn ⇒ λn=2nπr1.

Now, for n=4, we have:

λ4=8πr1=8πr.

Thank you.


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