the diffusion coffficientof an ideal gas is proportional to its mean free path and mean speed the absolute temperature of an ideal gas increased 4 times and its pressure is increased 2 times as a result the diffusion cofficient of a gas increased x times the value of x is?
Answer (1)
12th Jun, 2020
Hello!!!
Hope you are doing great!!!
Diffusion Coefficient ∝ λx u avg
λ =1/√ 2π σ ^2 .N
D.C ∝ u avg /√ 2π σ ^2 .N
No = P/KT
u avg ∝ √T
D.C ∝ T^3/2 / P
D.C2/D.C1 = 4*√4 /2
= 8/2
=4
Hope it helps!!!
1 like
Comments (0)
Related Questions
Trending Articles/News
AILET Cut Off 2025 (Out): Category Wise Cut-off Marks
12 minutes ago
CAT Topic Wise Weightage for VARC, Quant, and DILR
56 minutes ago
