the time period of a satellite of earth is 5h if the separation between the Earth and the satellite is increased to 4 times the previous value the new time period will become ?
Answer (1)
3rd Jul, 2020
Hello!!!
Hope you are doing great!!!
From Kepler's Third law,
T^2 is directly proportional to R^3
=(T1/T2)^2 = (R1/R2)^3
=(T1/T2)= (R1/R2)^3/2 = (1/4)^3/2
=T2/T1 = (4)^3/2
=8
=T2 = 8*T1
=8*5
=40hrs
Hope it helps!!
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