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the diffusion coffficientof an ideal gas is proportional to its mean free path and mean speed the absolute temperature of an ideal gas increased 4 times and its pressure is increased 2 times as a result the diffusion cofficient of a gas increased x times the value of x is?


oy64147 12th Jun, 2020
Answer (1)
Mounika Sonti 12th Jun, 2020

Hello!!!

Hope you are doing great!!!

Diffusion Coefficient ∝ λx u avg

λ =1/√ 2π  σ ^2 .N

D.C  ∝ u avg /√ 2π  σ ^2 .N

No = P/KT

u avg ∝ √T

D.C ∝ T^3/2 / P

D.C2/D.C1 = 4*√4 /2

= 8/2

=4

Hope it helps!!!

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