The energy in the earth state of a hydrogen atom is -13.6 ev. So the energy in the second excited state of he + ion is _____ ev.
Answer (1)
31st Aug, 2021
Hi aspirant,
For second excited state:
n=3 , We know that energy of a particle in an energy level is given by -13.6*z^2/n^2.
Therefore the energy of He+ ion in second excited stage is: -13.6*2^2/3^2 = -54.4/9 = -6.04 eV.
Note- For helium, atomic number (z=2)
Hope it helps!!
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